How Do the "fittype" function works

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somnath
somnath il 10 Ago 2015
Commentato: somnath il 10 Ago 2015
I am working on a project where I have got a piece of code where the fittype function has been used like this
ft = fittype( 'cconv(A.*exp(-x.*B), y,length(x))' , 'independent', {'x', 'y'}, 'dependent', 'z' );
where the circuler convolution is beeing done with two vectors A and B . My query is where the values of A and B comes from or how the values are beeing initialized .
  2 Commenti
Arun Badigannavar
Arun Badigannavar il 10 Ago 2015
Please elaborate your question, A, B depends on vector you choose,
somnath
somnath il 10 Ago 2015
Actually ai am studying a piece of code and After the fittype function the "fit" function is called , I want to know how the cconv((A.*exp(-x.*B), y,length(x)) function is called and A and B are estimated.

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Risposte (1)

Walter Roberson
Walter Roberson il 10 Ago 2015
fittype() does not initialize A or B in your example. fittype() creates a model that includes an anonymous function that will name A and B as parameters. Usually the fit() function is then used to determine the parameters, so what you want to know is how it initializes the values.
If no start points (the default value of an empty vector) are passed to the fit function, starting points for some library models are determined heuristically. For rational and Weibull models, and all custom nonlinear models, the toolbox selects default initial values for coefficients uniformly at random from the interval (0,1).
Yours is a custom nonlinear model.
  1 Commento
somnath
somnath il 10 Ago 2015
Thankyou very much . Now I got how the coeefs are initialized . Can you please help me understand how the circulerconvolution(with the function cconv()) is beeing done.

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