![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/642710/Screenshot_%D9%A2%D9%A0%D9%A2%D9%A1%D9%A0%D9%A6%D9%A0%D9%A2-%D9%A1%D9%A7%D9%A1%D9%A2%D9%A1%D9%A4.png)
generate a summation series
5 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
3(2+1)+4(3+2+1)+5(4+3+2+1)+6(5+...1)+...+1000(999+...+1).
How to write a matlab code to calculate the following summation without using for loop?
i can see the trend for 3(2+1) if the n = 1 (n+2)[((n+2)-1)+((n+2)-2)].
Assume the summation only sum until 6th term.
can we use array to solve this?
Risposta accettata
Più risposte (1)
Walter Roberson
il 13 Ago 2015
It does have a symbolic answer that you could find using nested symsum() if you have the symbolic toolbox.
But for a numeric answer: cumsum() and multiply by something gives a bunch of terms...
0 Commenti
Vedere anche
Prodotti
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!