Why am I getting NaN using interp2?

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macdommy74
macdommy74 il 26 Ago 2015
Commentato: macdommy74 il 26 Ago 2015
  • I have a 450*90 matrix of values
  • I want to sample the matrix at 100 random sample points
However, while my interp2 function runs without errors, my output results vector contains NaN values after the 90th index.
The code below results in me getting NaN for points after the 90th index of vals - why, and how do I correct it?
Shouldn't I be able to sample 1 point from the matrix, or 50, or 100, or 1000 points?
Code:
row_vect = 1:450;
col_vect = 1:90;
[X,Y] = meshgrid(col_vect, row_vect);
V = abs(rand(450,90));
Xq = row_vect(1:100);
Yq = randi(89, 1,100);
vals = interp2(X, Y, V, Xq', Yq');
Thanks

Risposta accettata

Torsten
Torsten il 26 Ago 2015
You try to extrapolate in Y-direction.
Read the description part for interp2 under
and you'll see why you get NaN for Y-values greater 90.
Best wishes
Torsten.
  3 Commenti
Torsten
Torsten il 26 Ago 2015
Use
[X,Y] = meshgrid(row_vect, col_vect);
instead of
[X,Y] = meshgrid(col_vect, row_vect);
Best wishes
Torsten.
macdommy74
macdommy74 il 26 Ago 2015
I think this worked - thanks a million!!

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Più risposte (1)

Walter Roberson
Walter Roberson il 26 Ago 2015
Your problem is your X not your Y. max(X(:)) is 90 because your first argument to meshgrid() is col_vec which is 1:90

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