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Yün Han on 20 Dec 2011
When I entered two arrays,
u = [1 2 3 4];v = [5 6 7 8];
and did the division using,
ans = 0.4023.
How to interpret the answer and what's the definition of array division like 'u/v' rather than element-wise 'u./v'?
C.J. Harris on 20 Dec 2011
Usually u/v is equal to u*inv(v) in matrix terms.
However, since v does not have an inverse Matlab will calculate the Moore-Penrose pseudoinverse of v instead. This can also be done directly:
u*pinv(v) = 0.4023
More Answers (2)
Malcolm Lidierth on 20 Dec 2011
Were you expecting this?
>> u = [1 2 3 4];v = [5 6 7 8];
0.2000 0.3333 0.4286 0.5000
Note the "." in
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