Array Division

235 views (last 30 days)
Yün Han on 20 Dec 2011
When I entered two arrays,
u = [1 2 3 4];v = [5 6 7 8];
and did the division using,
u/v
I got,
ans = 0.4023.
How to interpret the answer and what's the definition of array division like 'u/v' rather than element-wise 'u./v'?
Thanks.
0 CommentsShowHide -1 older comments

Sign in to comment.

Accepted Answer

C.J. Harris on 20 Dec 2011
Usually u/v is equal to u*inv(v) in matrix terms.
However, since v does not have an inverse Matlab will calculate the Moore-Penrose pseudoinverse of v instead. This can also be done directly:
u*pinv(v) = 0.4023
0 CommentsShowHide -1 older comments

Sign in to comment.

More Answers (2)

Malcolm Lidierth on 20 Dec 2011
Were you expecting this?
>> u = [1 2 3 4];v = [5 6 7 8];
>> u./v
ans =
0.2000 0.3333 0.4286 0.5000
Note the "." in
"./"
0 CommentsShowHide -1 older comments

Sign in to comment.

Sean de Wolski on 20 Dec 2011
doc mrdivide
is a good place to start.
0 CommentsShowHide -1 older comments

Sign in to comment.

Categories

Find more on Multidimensional Arrays in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by