Cutting a certain pattern from an array

4 views (last 30 days)
Hello everyone!
I have a simple question regarding deleting certain pattern from array. For example I have a random array
A=[1 2 3 4 5 6 0 0 0 0 1 2 3 4 5 6 7 8 9 10 0 0 0 0 ...]
I want to delete all fragments, built of four zeroes. So cut away all B=[0 0 0 0] from a 1d array.
How can I implement it?

Accepted Answer

C.J. Harris
C.J. Harris on 23 Sep 2015
A = [1 2 3 4 5 6 0 0 0 0 1 2 3 4 5 6 7 8 9 10 0 0 0 0];
B = [0 0 0 0];
C = A(setxor(cell2mat(arrayfun(@(x)(x:x+length(B)-1),strfind(A,B), 'UniformOutput', false)), 1:length(A)));
  2 Comments
beatlewalrus
beatlewalrus on 24 Sep 2015
Thank you, but it turned out to be not applicable in my case. I had to be more precise: i'm using MathScript node in LabView. So for example C=setxor(A,B) works ok in MatLab but doesn't work in LabVIEW

Sign in to comment.

More Answers (1)

Stephen23
Stephen23 on 23 Sep 2015
Edited: Stephen23 on 23 Sep 2015
>> A = [1,2,3,4,5,6,0,0,0,0,1,2,3,4,5,6,7,8,9,10,0,0,0,0];
>> B = [0,0,0,0];
>> +strrep(char(A),char(B),'')
ans =
1 2 3 4 5 6 1 2 3 4 5 6 7 8 9 10
  2 Comments
Stephen23
Stephen23 on 24 Sep 2015
True. It is also more than 100x faster than the accepted solution :)

Sign in to comment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by