Relative motion between Quaternions

30 visualizzazioni (ultimi 30 giorni)
BAN
BAN il 24 Set 2015
Modificato: James Tursa il 17 Dic 2019
I'm working on Quaternions. I wanna find out the relative motion between quaternions in MATLAB.
For example, I've
QuatA = [1283842729 -831786718 1290396116 1271562329] and
QuatB = [1313190417 1274713520 -845615766 1306114950]
How can I find how much QuatB is rotated with respect to QuatA?
Any help is appreciated.
Thanks.
  5 Commenti
BAN
BAN il 24 Set 2015
Yeah, I'm looking for angular motion. I'm sorry for not adding the proper tags. I'll edit.
BAN
BAN il 24 Set 2015
We can easily get the unit quaternions by normalizing it. I don't have any problem converting it to unit quaternions. But I don't understand how to get the relative motion.

Accedi per commentare.

Risposte (2)

James Tursa
James Tursa il 24 Set 2015
Modificato: James Tursa il 24 Set 2015
In general, for unit quaternions you would multiply the conjugate of one times the other, and then extract the angle and rotation axis from that. Be sure to do a quaternion multiply, not a regular multiply. Also be sure the quaternion multiply routine you are using assumes the scalar is in the same spot (1st or 4th) as the quaternions you have. You would have to divide your quaternions above by their respective norms to apply this technique, but not knowing what these quaternions represent I can't advise if this is the correct procedure or not.
  8 Commenti
Aitor Burdaspar
Aitor Burdaspar il 17 Dic 2019
Hello Manikya,
I have exactly the same problem as yours. Did you finally solve it?
Best regards,
James Tursa
James Tursa il 17 Dic 2019
Modificato: James Tursa il 17 Dic 2019
There is a fundamental misunderstanding of how to work with quaternions and Euler Angle sequences. In the first place, Euler Angle sequences do not behave linearly. That is, if you have a (yaw1,pitch1,roll1) sequence followed by a (yaw2,pitch2,roll2) sequence, you should not be expecting the result to be the same as a (yaw1+yaw2,pitch1+pitch2,roll1+roll2) sequence. Sequential rotations simply do not behave that way. So the subtractions you are doing (30-10, 40-10, 50-10) to get your "expected" result is simply not true with regards to sequential rotations.
In particular, I will use a couple of example coordinate frames to illustrate the issue.
Suppose q1 and q2 are both ECI_to_BODY quaternions. I.e.,
q1 = ECI_to_BODY1 (BODY1 being the BODY frame orientation for q1)
q2 = ECI_to_BODY2 (BODY2 being the BODY frame orientation for q2)
Then
q3 = conj(ECI_to_BODY2) * ECI_to_BODY1
= BODY2_to_ECI * ECI_to_BODY1
= BODY2_to_BODY1
So q3 represents a rotation between the two end BODY frames for the quaternions. Note that q3 is not another ECI_to_BODY quaternion. Since it is not another ECI_to_BODY quaternion, you should not expect the angles associated with it to be the same as what you get from a straight subtraction of your q1 and q2 angles.
Side note: The default order for the angles is y,p,r and not r,p,y.

Accedi per commentare.


Mo
Mo il 3 Giu 2018
How is this method used for a matrix? It seems "norm(A)" for a quaternion matrix is different. I appreciate any help.
  1 Commento
Luca Pozzi
Luca Pozzi il 11 Giu 2018
If A is an nx4 matrix (a 'column' of quaternions) the following code should work:
for i=1:size(A,1) % for each row of A
Anorm(i,:)=norm(A(i,:)); % dividing a row by its norm
end
norm(A) returns the norm of the whole matrix A, the for cycle here above allows you to normalize every single row of the matrix (i.e. every quaternion) instead. Hope this helps!

Accedi per commentare.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by