whats wrong with the code?
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function fx=f(x)
for i=1:length(x)
if x(i)<0
fx(i)=x(i);
elseif x(i)==0:pi/2;
fx(i)=sin(x(i));
else
fx(i)=(sin(x(i)))
end
end
end
Risposte (2)
x(i)==0:pi/2
compares x(i) to 0 and 1 (largest integer below pi/2) and gives the result in matrix of size 1x2. A matrix is considered to be true if all values are nonzero. Since x cannot be 0 and 1 at the same time, this never becomes true.
The code after else gives the same result as in the elseif before, so it does not make sense to differ between the two cases.
You don't need a for loop but you can use logical indexing to write your code, e.g.
fx(x<0) = x(x<0);
fx(x>=0 & x <= pi/2) = sin(x(x>=0 & x <= pi/2));
fx(x>pi/2) = -sin(x>pi/2);
Star Strider
il 7 Ott 2015
I would re-code your elseif line to:
elseif (x(i)>=0) & (x(i) <= pi/2)
1 Commento
Image Analyst
il 7 Ott 2015
Why & instead of &&?
Questa domanda è chiusa.
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