Azzera filtri
Azzera filtri

help with for loop matrix size

1 visualizzazione (ultimi 30 giorni)
kyle mikkola
kyle mikkola il 9 Ott 2015
Modificato: Stephen23 il 9 Ott 2015
% Initial values
h(1) = 0;
rho(1)= po*M/(R*To);
t(1) = 0;
vy(1) = 0;
dt = 1;
p(1) = po;
T(1) = To;
x(1) = 0;
vx(1) = 0;
Fdy(1)= 0;
Fdx(1)= 0;
% Position for loop
for i=1:480
m1(i) = ms + mt + ml*(1-t(i)/Tt) + mr + ms*(1-t(i)/Tb); % Mass Stage 1
g(i) = go * (re/(re+h(i)))^2; % Gravitational Acceleration Above Earth
Fdy(i) = .5 * rho(i) * vy(i)^2 * Cd *A; % Drag Force y-direction
rho(i) = (p(i) * M)/(R*T(i)); % Air Density
p(i) = po * (1-(L*h(i)/To))^(g(i)*M/(R*L)); % Air Pressure
T(i) = To - L * h(i); % Air Temperature
Fdx(i) = .5 * rho(i) * vx(i)^2 * Cd *A; % Drag Force x-direction
t(i+1)=t(i)+dt;
x(i+1)=x(i)+dt*(vx(i));
vx(i+1)=vx(i)+dt*(FTx1-Fdx(i))/m1(i);
h(i+1)=h(i)+dt*(vy(i));
vy(i+1)=vy(i)+dt*((FTy1/m1(i))+((vx(i)^2)/(re+h(i)))-g(i)-(Fdy(i)/m1(i)));
end
When I run this loop it says that rho(2) does not exist. It seems that the loop is not calculating a new value for rho every step. How should I fix this?
Thanks in advance
  1 Commento
kyle mikkola
kyle mikkola il 9 Ott 2015
I thought that make rho(1)=something just means that i set the first rho value and then the loop would update every value after that? How should I change this?

Accedi per commentare.

Risposta accettata

Walter Roberson
Walter Roberson il 9 Ott 2015
You currently have
Fdy(i) = .5 * rho(i) * vy(i)^2 * Cd *A; % Drag Force y-direction
rho(i) = (p(i) * M)/(R*T(i)); % Air Density
You need to exchange those two lines so rho(i) is set before it is used.

Più risposte (1)

Stalin Samuel
Stalin Samuel il 9 Ott 2015
In the line rho(1)= po*M/(R*To); you define that size of rho is 1.But you are accessing the values from 1 to 480.So it says that rho(2) does not exist.
  1 Commento
Stalin Samuel
Stalin Samuel il 9 Ott 2015
Modificato: Walter Roberson il 9 Ott 2015
h = 0;
rho= po*M/(R*To);
t = 0;
vy= 0;
dt = 1;
p= po;
T= To;
x = 0;
vx= 0;
Fdy= 0;
Fdx= 0;

Accedi per commentare.

Categorie

Scopri di più su Programming in Help Center e File Exchange

Tag

Non è stata ancora inserito alcun tag.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by