Finding small vector in big vector

Hey everybody,
I am desperately looking for a function that can find a small vector inside a big vector. Ismember and interesect just wouldn't do it right :(
Let's say I have the two vectors x = [ 7 6 9 7 4 3 7 9 0 7 4 3 2 6 7 0 7 5 ]; y = [ 4 3 2 6 ]
As a result I would like to have ans = [ 11 12 13 14 ]
so only the coordinates of where the values are in the correct sequence. Is there anything that can do that?
Thanks in advance!

 Risposta accettata

Try this:
x = [ 7 6 9 7 4 3 7 9 0 7 4 3 2 6 7 0 7 5 ];
y = [ 4 3 2 6 ];
% As a result I would like to have ans = [ 11 12 13 14 ]
out = strfind(x, y) + [0:length(y)-1]

2 Commenti

Lennart
Lennart il 21 Ott 2015
Modificato: Image Analyst il 21 Ott 2015
Wohoo awesome. Thank you guys so much! That just works perfectly. Actually the strfind itself is just what I need, but the idea of "+[0 : length(y)-1] " is quite needed as well.
You're welcome. strfind(x, y) finds only 11 - the start of the sequence - while adding that other vector gives you [11,12,13,14] which is what you said you wanted.

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Più risposte (2)

James Tursa
James Tursa il 20 Ott 2015
Modificato: James Tursa il 20 Ott 2015

1 voto

I am not on a machine with MATLAB at the moment to test this, but maybe try the strfind(x,y) function to see if it works with doubles (even though the doc doesn't indicate that it does).

3 Commenti

It does. The numbers are internally casted to char. For compatibility with other programs you can use strfind(char(x),char(y)).
@Alexander Paul "The numbers are internally casted to char."
I don't think so, if it was, the result of the two last commands would be indentiical
d = double('a')+0.1;
a = 'a';
strfind(d,a)
ans = []
strfind(char(d),char(a))
ans = 1
You are right. I checked it only with uint8.

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Matlab Pro
Matlab Pro il 12 Mag 2024

0 voti

Hi
A small improvement where the sub-vector is found more than once...
x = x(:)'; % Make sure data is a Row vector
ix = strfind(x, y);
if length(ix)>1 % Fix cases where y is found more than once
idx = [1:length(y)] + ix(1)-1; % Indexes of 1st occurance
else
idx = strfind(x, y) + [0:length(y)-1];
end

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