How to control output of a function ?

2 visualizzazioni (ultimi 30 giorni)
Jacky Jo
Jacky Jo il 25 Ott 2015
Modificato: Jacky Jo il 25 Ott 2015
I have written a function for spherical harmonics in which I want to control the ' Plotting area ' in such a way that, when we call the function into a variable, (i.e, lets say variable X= Plt( 10,30)*) I don't wanna show the plotting part. Otherwise (i.e, if the function _ Plt(10,30)* calling in a command window or somewhere in any other scripts, the plotting part of the function should run/ show the plots. The code has given below. (I have also attached the Plt.m* file with this.) Please give me an idea/ answer.... Thanks in advance.!
function [ P_bar ] = Plt( Degree_or_Order, Theta_In_Degree )
%%Content
%---------------------------------Plotting of Data--------------------------------
if grid_legth>1 % Works if ''theta'' is a grid of angles.
r=0;
for m=0:M
figure; width=1;
for L=r:L_max
PP=reshape(P_bar(L+1,m+1,1:grid_legth),1,grid_legth);
plot(T,PP,'linewidth',(1+(width/10)),'Color',rand(1,3));
hold on; grid on; width=width+1;
end
title(['Plote of P_(_:_,_' num2str(m) '_)']);
xlabel('Co-Latitude[Degree]');
[Lidx,Midx] = ndgrid(r:L_max,m);
legends = cellstr(num2str([Lidx(:),Midx(:)],'L = %d, M = %d'));
legend(legends,'Location','NorthEastOutside');
r=r+1;
end
figure;
PP=reshape(P_bar(L_max+1,M+1,1:grid_legth),1,grid_legth);
plot(T,PP,'linewidth',2); grid on;
xlabel('Co-Latitude[Degree]');
title(['Plote of P(' num2str(L_max) ',' num2str(M) ')']);
elseif grid_legth==1 % Works for a perticular co-latitude.
figure;
for m=0:M
a = linspace(10,150,L_max+1);
scatter(0:L_max,P_bar(:,m+1),a,'filled');
hold on; grid on;
end
[Midx] = ndgrid(0:M);
legends = cellstr(num2str([Midx(:)],' M = %d'));
legend(legends,'Location','NorthEastOutside');
title(['Scatter of P(' num2str(L_max) ',' num2str(m) ') with theta= ' num2str(T) ' degree']);
xlabel('Degree of Legendre Function (0 to L_m_a_x)');
end
end

Risposta accettata

Walter Roberson
Walter Roberson il 25 Ott 2015
nargout is 0 if there is no assignment implied in the way it was called
  1 Commento
Jacky Jo
Jacky Jo il 25 Ott 2015
Yes.... It's working... Thank you very much, Walter Roberson!

Accedi per commentare.

Più risposte (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by