Find prefix and postfix in a string

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pamela sulis
pamela sulis il 18 Nov 2015
Commentato: pamela sulis il 18 Nov 2015
Hi! I have a cell array (106x1) of strings, I want to find a prefix in every string and, after find the postfix, count the number of different items. Example
'0(012)(02)3(26)'
'(03)2(12)04)'
'(45)(02)(35)21'
'46(15)212'
For the prefix '01' the postfix are:
'(_2)(02)3(26)'
'(_2)04'
'3'
now i want to count the items more frequent: 0, 2, _2
Can you help me? Thanks
  2 Commenti
Guillaume
Guillaume il 18 Nov 2015
In your last two lines, I can't see any '01', so shouldn't the output be:
'(_2)(02)3(26)'
'(_2)04'
''
''
I also note that in your output you include the '(' that is before the prefix (and hence is not a postfix). Is that correct and is there any other symbol that follows this rule?
You've not explained what constitute an item, so I've no idea how you come about '0', '2', and '_2' being the most frequent. Why isn't '(' or ')' the most frequent item?
pamela sulis
pamela sulis il 18 Nov 2015
Modificato: pamela sulis il 18 Nov 2015
Yes, I made a mistake! After I have found the prefix, I want to find the elements more frequent in postfix. That in this case are 0,2 and (_2) but i have no idea how to do this. I have tried to find postfix in this way:
for k=1:106
a(k)= regexp(TrajCompact(k,1), '01', 'split');
end

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Guillaume
Guillaume il 18 Nov 2015
You can't have a regex that returns the before and after of a sequence of characters without that sequence of characters, but you can do your search and replace in two steps
in = {'0(012)(02)3(26)'
'(03)2(012)04)'
'(45)(02)(35)21'
'46(15)212'};
matches = regexp(in, '\(?01.*', 'match', 'once');
out = regexprep(matches, '01', '_') %note that you could simply use strrep
As for your question about frequency, I still have no idea what constitute an item or element.
  3 Commenti
Guillaume
Guillaume il 18 Nov 2015
Well , 0, 1, 2, 3, 4,... are individual digits. Yet, you also include _2 in your items which is made of two characters.

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