How to index cell Matrix with a logical matrix?

Hello all, I tried to index a cell matrix with logical matrix, but it does not return me the correct output.
I want to:
Index: A ={'a','b','c','d'; 'a','b','c','d'; 'a','b','c','d'}
Matrix: B =[1,0,1,0; 0,1,1,0; 0,0,1,1]
Output: C =['a','','c',''; '','b','c',''; '','','c','d'];
I tried 'C=A(logical(B));' but without success.
Could someone help me, please?
Thank you!

2 Commenti

Please note that
A =['a','b','c','d'; 'a','b','c','d'; 'a','b','c','d']
is not a cell array. It is a plain matrix of character and is the same as:
A = ['abcd';'abcd';'abcd'];
A cell array is:
A = {'a','b','c','d'; 'a','b','c','d'; 'a','b','c','d'}
Note the use of curly brackets. The distinction is important for your desired output since
C =['a','','c',''; '','b','c',''; '','','c','d'];
is the same as
C = ['ac'; 'bc'; 'cd'];
Sorry Guillaume, my fault. Actually is exactly as you said (A ={'a','b','c','d'; 'a','b','c','d'; 'a','b','c','d'}). I only typed the question incorrectly.

Accedi per commentare.

 Risposta accettata

Assuming you indeed have a cell array (unlike your example):
A = {'a','b','c','d'; 'a','b','c','d'; 'a','b','c','d'}
B = logical([1,0,1,0; 0,1,1,0; 0,0,1,1]);
%option 1: create an empty cell array and use logical indexing to copy A
C = cell(size(A));
C(B) = A(B)
%option 2: copy A, and use logical indexing to replace unwanted elements
D = A;
D(~B) = {''}
Note that for all intent and purposes '' and [] are the same, even if matlab does not display them the same
isequal(C, D) %returns true

5 Commenti

Guillaume, your solution works great! I don't know what I did before. Thank you !!!
No, Guillaume's solution gives you the remaining values for each row, i.e.,
C =
'a' [] 'c' []
[] 'b' 'c' []
[] [] 'c' 'd'
or
D =
'a' '' 'c' ''
'' 'b' 'c' ''
'' '' 'c' 'd'
What do you want if you are not happy with this?
You're correct Thorsen. Guillaume's solution works fine. Thank you !
Guillaume, when I do: D(~B) = {''}, the MATLAB throws an error "Function 'subsindex' is not defined for values of class 'cell'." Could it be due to version? maybe 2016 does not support this way of indexing? Thanks,
@Thorsten: Using option 2 does indeed give you an array with "empty" values (actually ' '). You can however just assign [ ] directly, which MATLAB interprets as deletion command.
%option 2: copy A, and use logical indexing to replace unwanted elements
D = A;
D(~B) = []; % this will delete all arguments where B(i) ~= true. -> before: {''}
This question - solving the problem for a 2D-cell array - may also help. A full alternative to the snippet above would be:
% copy A, and use logical indexing to replace unwanted {elements} with {''}
D = A;
D(~B) = {''};
% Identify empty cells
idx = cellfun(@isempty, D);
% Delete rows with empty cell
D(~any(idx)) = [];

Accedi per commentare.

Più risposte (1)

Thorsten
Thorsten il 26 Nov 2015
Modificato: Thorsten il 26 Nov 2015
Not exactly want you want, but close:
C = A;
C(B ~= 1) = ' '

1 Commento

Thorsen, The problem of this solution is that the output is the follow array:
C= {'a' 'b' 'c' 'c' 'c' 'd'}
And I need to know which is the remaining values for each row.
Thank you!!

Accedi per commentare.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by