How to find neighbor matrix?

This is some code i write:

for i=1:h   %h=height of the image
   for j=1:w %w=width of image
       if (i,j)==1  %1 is the border
           if (i,j-1) ~=1 && if(i,j+1) ~=1
           table(j-1,j+1) =1
           table(j+1,j-1) =1 

 for j=1:w %w=width of image
   for i=1:h   %h=height of the image
         if (j,1)==1  %1 is the border
             if (j,i-1) ~=1 && if(j,i+1) ~=1
             table(i-1,i+1) =1
             table(i+1,i-1) =1

I hope loop horizontal and vertical to find the neighbor matrix dont care of diagonal situation.

As long as it read x then read 1 then read y then (x,y) and(y,x)=1

How to solve this?

A=
  1 1 1 1 1 1 1 1 1 1
  1 2 2 1 3 3 1 4 4 1 
  1 2 2 1 3 1 5 5 5 1
  1 1 1 1 1 1 1 1 1 1

result=
     2 3 4 5
  2  1 1 0 0 
  3  1 1 1 1
  4  0 1 1 1
  5  0 1 1 1

[Walter Roberson]

table((i-1),(j+1)) attempts to index table(0,2) because i starts at 1.

Answer 1

[Walter Roberson]

table = (A == 1);
s = max(size(table,1),size(table,2));
if s ~= size(table,1) || s ~= size(table,2)
   table(s,s) = false;    %make it square
end
table = table | table.';    %make it symmetric

[Tan Wen Kun]

Your solution just extracted 1 from the labelimg, that not I want.

What I want is when is label= 1 2 1 3 1

I made table(2,3)=1 and table(3,2)=1

Attempted to access labelimg(214,0); index must be a positive integer or logical.

for i=1:max(labelimg(:))   
   for j=1:max(labelimg(:))
       if labelimg(i,j)==1  %1 is the border
           if labelimg(i,j-1) ~=1  
               if labelimg(i,j+1) ~=1
                   table(j-1,j+1) =1 ;
                   table(j+1,j-1) =1 ;

how to solve this when I using j-1 when loop first element got problem and also j+1 when loop last element?How to solve the index out of bound?

[Walter Roberson]

maxlab = max(labelimg(:));
for i = 1 : maxlab
  for j = 2 : maxlab - 1

Now you can test labelimg(i,j-1) and labelimg(i,j+1)