I get "Index exceeds matrix dimensions" in Signal Processing

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When I try running my function with what was asked from me in my class thhis happens; can someone please help me:
Where S_1 to S_3 are attached
[vel1,corrcoef1] = p2( S_1,S_2,S_3,2048 )
Index exceeds matrix dimensions.
Error in p2 (line 9)
d1w=detrend(interp(d1(.5*i*fm+1:.5*fm(i+1)),20),'constant');
My code is this:
function [vel,corrcoef] = p2( Ss1,Ss2,Ss3,fm )
%Diferentials especifications
d1=Ss1-Ss2;
d2=Ss2-Ss3;
for i=0:313120
d1w=detrend(interp(d1(.5*i*fm+1:.5*fm(i+1)),20),'constant');
d2w=detrend(interp(d2(.5*i*fm+1:.5*fm(i+1)),20),'constant');
[corfun,lags]=xcorr(d1w,d2w);
fac=sqrt(sum(d1w.^2)*sum(d2w.^2));
normf=corfun/fac;
[corrcoef(i+1), pos]=max(normf);
delay=abs(lags(pos));
plot(lags,normf);
vel(i+1)=0.005/(delay/fm);
end
function is attached as well

Risposte (2)

Sam Muldoon
Sam Muldoon il 7 Dic 2015
Modificato: Sam Muldoon il 7 Dic 2015
"Index exceeds matrix dimensions" means you tried to access an element of an array either before the array's begining, or more likely, after the array's end.
For example, if A = [1, 2, 3], then A(247) doesn't make very much sense, does it? There are only three elements in the array, how on earth could you access a 247th element of it?
247 is the "index." The dimensions of A are one row, and three columns. The index exceeds the matrix dimensions.
  2 Commenti
Stephen23
Stephen23 il 7 Dic 2015
Modificato: Stephen23 il 7 Dic 2015
@Sam Muldoon: +1 for a clear explanation and example.

Accedi per commentare.


Walter Roberson
Walter Roberson il 7 Dic 2015
Your code has
d1w=detrend(interp(d1(.5*i*fm+1:.5*fm(i+1)),20),'constant');
Notice the fm(i+1) . That is a request to index fm at position i+1 . Perhaps you omitted a multiplication,
d1w=detrend(interp(d1(.5*i*fm+1:.5*fm*(i+1)),20),'constant');

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