What's wrong with this parfor loop?
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When I try to run the following parfor loop, Matlab returns the error claiming that A cannot be classified.
N = 10;
T = 3;
A = zeros(N,T);
parfor i = 1:1:N
for t = 1:1:T
A(i,t) = rand(1,1);
end
end
Why isn't A considered to be a sliced output variable? The following modification works just fine.
N = 10;
T = 3;
A = zeros(N,T);
parfor i = 1:1:N
A(i,1) = rand(1,1);
end
So it seems to be something to do with the inner loop over t. From reading the help document on sliced variables, I don't understand why this inner loop would make a difference.
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Più risposte (1)
Walter Roberson
il 11 Dic 2015
N = 10;
T = 3;
A = zeros(N,T);
parfor i = 1:1:N
v = zeros(1,T);
for t = 1:1:T
v(1,t) = rand(1,1);
end
A(i, :) = v;
end
1 Commento
even coil
il 11 Dic 2015
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