Sum each element in a matrix with the previous elements on the same diagonal
1 visualizzazione (ultimi 30 giorni)
Mostra commenti meno recenti
I'm looking for an "efficient way", that will work on larger matrices like 2000 by 2000 in reasonable time, to do this operation on a given square symmetric and anti-symmetric matrix (Hankel matrix)
A =[1 2 3;
2 3 4;
3 4 5;];
Then the output should be
B = [1 2 3;
2 4 6;
3 6 9;]
0 Commenti
Risposte (3)
Walter Roberson
il 3 Feb 2016
No. Your B(2,1) is 4 even then there is nothing proceeding it on the same diagonal from upper left to lower right. But 4 is the cumulative sum from the diagonals from the upper right to the lower left, the anti-diagonals. This establishes that you want both diagonal and anti-diagonal cumulative sums to be taken. But your B(3,1) is 4, which is not the cumulative sum along the anti-diagonal
x x 3
x 3 x
4 x x
Therefore there is no rule for what values should appear along the left column of B, and therefore the result cannot be computed.
Ajay Goyal
il 3 Feb 2016
Modificato: Ajay Goyal
il 3 Feb 2016
Simple Brother, Use a(i,j)=a(i,j)+a(i-1,j-1) in your double loop (for i=1:2000(for rows); for j=1:2000(for columns)) Thanks for accepting the answer formally
1 Commento
Vedere anche
Categorie
Scopri di più su Operating on Diagonal Matrices in Help Center e File Exchange
Prodotti
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!