Find one array into another

Hello everyone!

I've found similar discussions, but haven't found a solution for my case. I have an array A, for example [0 0 1 0 0 1 1 0 0 1 1 0 0 0] and want to know the number of times, when A consists array B=[ 1 1] - two consecutive ones. Not the number of ones in A in general, but a certain pattern. I can do this by making a cycle comparing element by element, but if the desired pattern is long it's not a good idea. Thank you in advance!

Answer 1

[Stephen23]

Funnily enough strfind is really good for this task:

numel(strfind(A,B))

[goodermes]

thank you for a quick response! and a tricky question, is there the similar function for rows? if for example A=[1; 1; 0; 0] and b=[1;1] ?

[Stephen23]

1. for simple column vectors transpose them to become row vectors.
2. for matrices, you could try this FEX submission:

http://www.mathworks.com/matlabcentral/fileexchange/23998-findsubmat

Answer 2

[Jos (10584)]

for integer values you can (often) use the strfind trick

A = [1 1 0 1 0 1 1 1 0 1 0 1 0 1 1 0]  
B = [1 1 0]
idx strfind(A,B)
% ans =    1     7    14