Computing and Ploting Fourier transform

2 visualizzazioni (ultimi 30 giorni)
How can i use the fft command to transform a rectangular pulse to sinc function and plot the sinc function, i'm using a very traditional way to compute the fourier transform and plot it, but this way is too slow, when i use the fft command and try to plot, the ploting of the magnitude is only the pins or a spike, i need the plot to be a sinc function as the picture that i attached here, also i'm using the same method to compute the inverse fourier transform so i also need to use the ifft command, can anyone help?
if true
p = heaviside(t+1)-heaviside(t-1);
k = 0;
F=zeros(1,8001);
for f= -4:0.001:4
k=k+1;
F(k) = trapz(t,p.*exp(-1i*2*pi*f*t));
end
f = -4:0.001:4;
figure(1);
plot(f,F);
grid
end

Risposta accettata

Rick Rosson
Rick Rosson il 21 Feb 2016
Modificato: Rick Rosson il 21 Feb 2016
Fs = 8;
dt = 1/Fs;
N = 8000;
t = dt*(-N/2:N/2-1)';
dF = Fs/N;
f = -Fs/2:dF:Fs/2-dF;
p = heaviside(t+1)-heaviside(t-1);
P = dt*fftshift(fft(ifftshift(p)));
figure;
plot(f,real(P));
grid on;
  1 Commento
omarahmed.m
omarahmed.m il 21 Feb 2016
Thank you for your response, Could you just specify this command "P = dt*fftshift(fft(ifftshift(p)));", why it consist of fftshift of fft of ifftshift, and why multiplying by "dt". thank you very much.

Accedi per commentare.

Più risposte (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by