problem with matlab index

hi

i'm rajashekar from JNTU doing my M.tech

i have been trying to solve an equation and it requires me repaet this equation in a loop and store values . the equation is

I(n*td) = sin(((alpha(n)./2)) + (((beta./2)).*(I((n-1)*td)))).^2;

here n is an integer but td is in micro or milli seconds and matlab does not allow for storing n*td that gives a decimal values. is there any way i can save my iteration results in a matrix?

thank you

Answer 1

[Walter Roberson]

Your only use of td is to multiply the index in to I. So unless there are reasons not to, just leave td out:

I = zeros(FinalValueIndex,1);
I(1) = TheInitialValue;
for n = 2 : FinalValueIndex
  I(n) = sin(alpha(n)./2) + (beta ./2 .* I(n-1)).^2;
end

Unless, that is, beta is a vector.

[rajashekar]

yes i was doing so too....but the more i think about it i thought i might be wrong....because theoretically td is the time delay and the index there is the time....so i basically should multiply time and time delay....time can be integer but delay is in micro seconds...i should multiply both and repeat the iteration....beta is constant...can you explain if i use above code you told me how is the delay introduced into the code which i'm really confused about....

[rajashekar]

also my original equation which i have to simulate is

I(t)=sin(((alpha(t)./2)) + (((beta./2)).*(I((t-td)))).^2;

where t is time and td is time delay....can you tell me how do i simulate this?

[rajashekar]

any ideas?