Reading a CSV file with header and times

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Steven
Steven il 29 Gen 2012
Good Afternoon,
I am having difficulty loading csv files into Matlab. The problem seems to be with the header (which contains strings) and the data values in two of the columns (they contain time values in 00:00 format).
I am able to ignore the header through use of the 'csvread' function, but Matlab won't load the time values and gives me the below errors.
EDU>> x = csvread('SUNY_070054005.csv', 1, 0)
??? Error using ==> dlmread at 145 Mismatch between file and format string. Trouble reading number from file (row 1, field 5) ==> :15,0
Error in ==> csvread at 50 m=dlmread(filename, ',', r, c);
The data in the CSV file are in the following format...
Date,Itime,Uglo,Udir,Udif,Stime,Sglo,Sdir,Sdif
1998-01-01,00:15,0,0,0,01:00,0,0,0
1998-01-01,01:15,0,0,0,02:00,0,0,0
I would use the wizard, but I have to import 281 csv files.
Any help would be appreciated.
Many Thanks,
Steven

Risposta accettata

Sven
Sven il 30 Gen 2012
Hi Steven,
The string you've got for the dates and times aren't automatically recognised as simple dates - you'll need to read them in as strings:
fid = fopen('myFile.txt')
HDRS = textscan(fid,'%s %s %s %s %s %s %s %s %s',1, 'delimiter',',')
DATA = textscan(fid,'%s %s %d %d %d %s %d %d %d','delimiter',',')
fclose(fid)
outCell = cell(size(DATA{1},1), length(HDRS));
for i = 1:length(HDRS)
if isnumeric(DATA{i})
outCell(:,i) = num2cell(DATA{i});
else
outCell(:,i) = DATA{i};
end
end
myStruct = cell2struct(outCell, [HDRS{:}], 2);
Does this work for you? It worked for a small text file that I made from your input. You can convert stringed dates (and times) using the datestr function.
  3 Commenti
Sven
Sven il 31 Gen 2012
Hi Steven, I've updated the answer to do this second part in a way that I thought would be useful. Keep in mind that I've used "%d" which will convert all numbers in the text files to integers. Use "%f" if you need floats.
Steven
Steven il 5 Feb 2012
Sven,
I tried the code you provided and it works :-). I wish I could have thanked you sooner, but I wasn't able to get on earlier in the week.
Thanks again :-)
-Steven

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Stanislav
Stanislav il 26 Mar 2013
Modificato: Stanislav il 26 Mar 2013
The easiest way for me is :
path='C:\folder1\folder2\';
data = 'data.xls';
data = dataset('xlsfile',sprintf('%s\%s', path,data));
Of cource you could also do the following:
[data,path] = uigetfile('C:\folder1\folder2\*.xls');
data = dataset('xlsfile',sprintf('%s\%s', path,data));

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