Roots of a function
Mostra commenti meno recenti
I have two equations:
y1 = 2sinx1;
y2 = 2cos^2(x1) + 3sin(2x2+3);
here y1 = 0 while y2 = 1.
Can anyone please tell me which approach would be the best to find out the values of x1 and x2.
Thank you.
1 Commento
Torsten
il 30 Mar 2016
x1=0
x2=(asin(-1/3)-3)/2
Best wishes
Torsten.
Risposta accettata
Più risposte (1)
Vlad Miloserdov
il 30 Mar 2016
if you still need this
A=solve('0 = 2*sin(x1)','1 = 2*cos(x1)^2 + 3*sin(2*x2+3)','x1','x2');
% first ans
A.x1(1)
A.x2(1)
% second ans
A.x1(2)
A.x2(2)
5 Commenti
Muhammad Umar Farooq
il 31 Mar 2016
Torsten
il 31 Mar 2016
You have two equations - thus you will need MATLAB's "fsolve".
Best wishes
Torsten.
Muhammad Umar Farooq
il 31 Mar 2016
Torsten
il 31 Mar 2016
Please show your code.
Best wishes
Torsten.
Muhammad Umar Farooq
il 31 Mar 2016
Categorie
Scopri di più su Function Creation in Centro assistenza e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!