Azzera filtri
Azzera filtri

Problems with parfor in class method

3 visualizzazioni (ultimi 30 giorni)
Bananach
Bananach il 17 Apr 2016
Modificato: Matt J il 17 Apr 2016
If I run
F=Foo(1);
F.A=pi;
F.bar();
where
classdef Foo
properties
A;
sz;
end
methods
function obj = Foo(sz)
obj.sz=sz;
end
function obj=set.A(obj,A)
if size(A)==obj.sz
obj.A=reshape(A,numel(A),[]);
end
end
function []=bar(obj)
parfor i=1:1
obj.A(1);
end
end
end
end
then I get
Error using Foo/bar (line 16)
Index exceeds matrix dimensions.
Error in test (line 4)
F.bar();
The error disappears when I replace the parfor-loop with a regular for-loop.
I get a warning in my editor on the line "if size(A)==obj.sz", saying "A set method for a non-dependent property should not access another property". However, if I make the variable "A" dependent, then I can't define a set method.
EDIT: I found out that the error also disappears when I declare "sz" first, and then "A".

Risposta accettata

Matt J
Matt J il 17 Apr 2016
Modificato: Matt J il 17 Apr 2016
Very strange indeed. However, the following seems to solve all problems.
classdef Foo
properties
Adata;
sz;
end
properties (Dependent)
A;
end
methods
function obj = myclass(sz)
obj.sz=sz;
end
function obj=set.A(obj,val)
if isequal(size(val), obj.sz) || isscalar(val)
obj.Adata=val(:);
else
obj.Adata=val;
end
end
function A=get.A(obj)
A=obj.Adata;
end
function bar(obj)
parfor i=1:1
obj.A(1),
end
end
end
end
  3 Commenti
Bananach
Bananach il 17 Apr 2016
Also, note my edit: I can fix my code by declaring "sz" first
Matt J
Matt J il 17 Apr 2016
Modificato: Matt J il 17 Apr 2016
I've edited my post with a variation that does the reshaping in the set.A method.
It might be a bug, and certainly wouldn't hurt to report. My theory, though, is that the warning you were getting about set.A is somehow the cause of the parfor error. When A is converted to a Dependent property with proper set/get methods defined, I see no error thrown by bar().

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su Loops and Conditional Statements in Help Center e File Exchange

Prodotti

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by