How to remove rows having repeating elements from a matrix?
1 visualizzazione (ultimi 30 giorni)
Mostra commenti meno recenti
Susmita
il 25 Apr 2016
Commentato: David Wagener
il 1 Dic 2019
If I have a matrix A=[ 1 2 1 4; 1 2 3 4; 3 2 1 4; 3 3 2 1] then I want a matrix as B=[ 1 2 3 4; 3 2 1 4] so that both the 1st and 4th row will be deleted as they have repeated elements. pls help me to find out the code.
0 Commenti
Risposta accettata
Roger Stafford
il 25 Apr 2016
Modificato: Roger Stafford
il 27 Apr 2016
t = false(1,size(A,1));
for k = 1:size(A,1)
u = unique(A(k,:));
t(k) = size(u,2)==size(A,2);
end
B = A(t,:); % Rows with repeated elements deleted
Più risposte (1)
Baltam
il 25 Apr 2016
The below method is not elegant but it works.
A=[ 1 2 1 4; 1 2 3 4; 3 2 1 4; 3 3 2 1];
index = zeros(1,size(A,1));
for i = 1:size(A,1)
if numel(unique(A(i,:))) == numel(A(i,:))
index(i)=1;
end
end
index = logical(index);
B = A(index,:);
Kind regards,
Baltam
2 Commenti
David Wagener
il 1 Dic 2019
The second version shown here while not as elegant works better if you have a large matrix and are using parallel processing. I'm not an expert by any means but the second version did not overload my machine like the first one did.
Vedere anche
Categorie
Scopri di più su Logical in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!