average

i have a 42*16384. how do i average it so that i get a new matrix of size 42*2048 (if N=2048 represents one revolution and N=16384 represents 8 revolutions).

Answer 1

[Andrei Bobrov]

data - your array [42x16384]

EDIT

out = mean(reshape(data,size(data,1),[],8),3);

eg:

data - your array [55x72000]

out = mean(reshape(data,size(data,1),[],3),3);

or

out = squeeze(mean(reshape(data,size(data,1),3,[]),2)) ;

[Lisa Justin]

thanks. Please how do i do the same with a matrix of 55*72000 so i get 55*24000 (where N=24000 represents one revolution and N=72000 represents 3 revolutions)?

[Andrei Bobrov]

out = mean(reshape(data.',size(data,2),[],3),3).'

[Lisa Justin]

i get an error message

??? Error using ==> reshape

Product of known dimensions, 216000, not divisible into total number of elements,

3960000.

[Lisa Justin]

I am still getting the same error message with

out = squeeze(mean(reshape(data.',size(data,2),8,[]),2)).'

[Andrei Bobrov]

see EDIT