What is the wrong with the following code?

3 visualizzazioni (ultimi 30 giorni)
address='1217 fayettevelle St., Durham, NC';
SERVER_URL = 'http://maps.google.com';
address = regexprep(address, ' ', '+');
queryUrl = sprintf('%s/maps/geo?output=xml&q=%s',SERVER_URL, address);
docNode = xmlread(queryUrl)
It is showing the following error:
Error using xmlread (line 97) Java exception occurred: java.io.FileNotFoundException: http://maps.google.com/maps/geo?output=xml&q=1217+fayettevelle+St.,+Durham,+NC
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source)
at org.apache.xerces.impl.XMLEntityManager.setupCurrentEntity(Unknown Source)
at org.apache.xerces.impl.XMLVersionDetector.determineDocVersion(Unknown Source)
at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
at org.apache.xerces.parsers.XMLParser.parse(Unknown Source)
at org.apache.xerces.parsers.DOMParser.parse(Unknown Source)
at org.apache.xerces.jaxp.DocumentBuilderImpl.parse(Unknown Source)
at javax.xml.parsers.DocumentBuilder.parse(Unknown Source)
Error in Untitled2 (line 11) docNode = xmlread(queryUrl)
  1 Commento
Adam
Adam il 6 Mag 2016
Modificato: Adam il 6 Mag 2016
It can't find the file. Check that the file you are giving it is actually a valid full path.

Accedi per commentare.

Risposta accettata

Guillaume
Guillaume il 6 Mag 2016
Modificato: Guillaume il 6 Mag 2016
xmlread does not read urls, only files. To read urls you can use webread. I believe the following should work if http://maps.google.com/maps/geo were a valid URL at (unfortunately, it 404):
address='1217 fayettevelle St., Durham, NC';
SERVER_URL = 'http://maps.google.com';
address = regexprep(address, ' ', '+');
fullurl = sprintf('%s/maps/geo', SERVER_URL);
domnode = webread(fullurl, 'output', 'xml', 'q', address, weboptions('ContentType', 'xmldom'))
  1 Commento
K M Ibrahim Khalilullah
K M Ibrahim Khalilullah il 10 Mag 2016
Modificato: K M Ibrahim Khalilullah il 10 Mag 2016
Thanks, At last I have solved. but xmlread can read urls....

Accedi per commentare.

Più risposte (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by