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Is there a way for creating n number of new rows from one row?

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Let my matrix be
a=[1 2 3 4
5 6 7 8]
Then I want to create n=8 new rows from the first row according to this logic.
newrow_1=firstrow +/- (rand()/k)* firstrow
And it goes on newrow_2.... till newrow_8.

Answers (1)

Ahmet Cecen
Ahmet Cecen on 19 May 2016
Edited: Ahmet Cecen on 19 May 2016
A much more robust version of that reference answer, especially if you need to repeat every row the same amount of times, and you have a lot of rows:
b = repmat(a',[4,1]);
c = reshape(b,[4,8])';
or:
b = repmat(a',[numberoftimestorepeat,1]);
c = reshape(b,[size(a,2),size(a,1)*numberoftimestorepeat])'

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