How to easily detect all the equal rows of an array with saving the indices of the elements?

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I have a matrix as shown here
A=[ -1 0 0;
-1 0 0;
-1 0 0;
-1 0 0;
1 0 0;
1 0 0;
] I want to detect all the equal rows in the matrix and build another matrix with the indices of the equal rows. For exemple here row1=rows2=row3=row4 and row5=row6... I want to have a matrix like this [1 2;1 3;1 4; 5 6]. I find a solution but it uses a lot of for loops so it's not fast enough when I apply it to a large matrix. Is there any easiest solution for this. Thank you.

Answers (1)

Ahmet Cecen
Ahmet Cecen on 19 May 2016
This does all of that:
[C,ia,ic] = unique(A,'rows')

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