pick one value per munite
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Hi all,
i have such an date time Array:
'18-May-2016 14:04:17'
'18-May-2016 14:05:07'
'18-May-2016 14:05:54'
'18-May-2016 14:06:43'
'18-May-2016 14:07:34'
'18-May-2016 14:08:25'
'18-May-2016 14:09:15'
'18-May-2016 14:10:07'
'18-May-2016 14:10:57'
'18-May-2016 14:11:48'
'18-May-2016 14:12:39'
'18-May-2016 14:13:30'
'18-May-2016 14:14:22'
'18-May-2016 14:15:12'
'18-May-2016 14:16:03'
'18-May-2016 14:16:54'
how could i clear the repeated munite values? for exemple : 18-May-2016 14:05:54 , '18-May-2016 14:10:07' and '18-May-2016 14:16:54'.
Thank you all
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Più risposte (1)
Azzi Abdelmalek
il 20 Mag 2016
Modificato: Azzi Abdelmalek
il 20 Mag 2016
A={'18-May-2016 14:04:17'
'18-May-2016 14:05:07'
'18-May-2016 14:05:54'
'18-May-2016 14:06:43'
'18-May-2016 14:07:34'
'18-May-2016 14:08:25'
'18-May-2016 14:09:15'
'18-May-2016 14:10:07'
'18-May-2016 14:10:57'
'18-May-2016 14:11:48'
'18-May-2016 14:12:39'
'18-May-2016 14:13:30'
'18-May-2016 14:14:22'
'18-May-2016 14:15:12'
'18-May-2016 14:16:03'
'18-May-2016 14:16:54'}
a=datevec(A,'dd-mm-yyyy HH:MM:SS')
min1=a(:,end-1)
[~,ii]=unique(min1,'stable');
out=A(ii,:)
2 Commenti
Rica
il 20 Mag 2016
@Azzi, please don't use min as a variable name (overrides the min function). You're teaching bad habits in your examples!
@Rica, well you're asking to remove duplicates and hence to obtain unique minutes. The unique function is the most appropriate for this. The length of your array is irrelevant, whichever scheme you could come up with will be slower than unique.
Also, I would recommend using datetime instead of datevec. As a matter of fact, I would simply convert the datestring array into datetime and just use that for future processing. datetime is a lot easier to use
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