How to take first three characters of string

3 visualizzazioni (ultimi 30 giorni)
Hi,
I have the below cell array:
MA0K123T0
MB0JHY210I9
AoTkU08
880KE21L
PMB456KU0
standard
MF0KET9
twist
MA0KL3
PMV09K
Now I want to filter as below:
If the name start with M or P, then take the first three characters otherwise keep original name. My output should be:
MA0
MB0
AoTkU08
880KE21L
PMB
standard
MF0
twist
MA0
PMV

Risposta accettata

Azzi Abdelmalek
Azzi Abdelmalek il 23 Mag 2016
Modificato: Azzi Abdelmalek il 23 Mag 2016
str={'MA0K123T0'
'MB0JHY210I9'
'AoTkU08'
'880KE21L'
'PMB456KU0'}
out=cellfun(@(x) regexprep(x,'\<(M|P).+',x(1:3)),str,'un',0)
  7 Commenti
Azzi Abdelmalek
Azzi Abdelmalek il 24 Mag 2016
This doesn't give the expected result (look at the new question in the hidden comment)
Azzi Abdelmalek
Azzi Abdelmalek il 24 Mag 2016
We can use dynamic expressions
match_expr = '(M|P)([a-zA-Z]?)([a-zA-Z]?)(.+)'
replace_expr='$1$2$3'
regexprep(str, match_expr, replace_expr)

Accedi per commentare.

Più risposte (1)

Guillaume
Guillaume il 23 Mag 2016
Modificato: Guillaume il 24 Mag 2016
Azzi's answer with to regex call seems unnecessarily complicated to me. The cellfun is also not required. This simple regex will do:
str = {'MA0K123T0'
'MB0JHY210I9'
'AoTkU08'
'880KE21L'
'PMB456KU0'}
out = regexp(str, '^[MP].{2}|.*', 'match', 'once')
Which basically says match M or P (the [MP]) at the beginning of the string (the ^) followed by any two characters (the .{2}) and if that does not match, match everything (the &#124.*)
edit for your updated question:
out = regexp(str, '^[MP][A-Za-z]?[A-Za-z]?|.*', 'match', 'once')

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