Simple find and replace program

I have a long list of values (rest time measurements of wild animals) where each row constitutes a 2 second time bin. Measurement was done in 250ms intervals so that the resulting data looks something like this:

0
2
1,75
0,75
2
2
2
0,25
0,75
...

I need to create a program that does the following:

1. Find the first instance of "2"
2. Check if there is a "2" right next to it
3. If yes, move to the value below/above (i.e.: find both non-2 neighbours)
4. Check if the sum of the two non-2 neigbours >=2
5. If yes, replace the largest one with a 2 and the smallest one with a 0
6. If no, ignore and move on
7. If both non-2 neighbours =1, replace randomly
8. Move on to the next instance of "2"

I tried to start coding this, but I am getting stuck within these nested for loops, and using the find function. I feel like there is a much easier way to do this, and maybe someone can start me on the right path?

count = 1
for i= 1:length(List) %For the length of the data list

    if List(i,1) == 2 %If row i (1,2,3,4,5...) equals 2
        count = count+1
        %check if the neighbours also = 2
         %Start a counter to check how high up it has to go. 
        if List(count,1) < 2 %Until the 
            find(List(Count,1)

        end
    end

end

Thanks,

Fry

[Stephen23]

@Frederik Theissen: Can you please give us complete input and output example vectors, so that we have something to run our code on and compare the output against.

[Walter Roberson]

Is the "0,75" intended to represent 3/4, which MATLAB would write as 0.75 ? Or is "0,75" intended to be a pair of values, [0 75] ?