How can I delete the continuously duplicated value and keep the last one in a cell array?
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Trung Hieu Le
il 9 Giu 2016
Commentato: Trung Hieu Le
il 10 Giu 2016
Hello,
I'm trying to delete the continuously duplicated value and keep the last one in a cell array. I try some ways but it does not work. Could you help me correct it?
My input data (around 4 million rows):
Symbol, Data, Time, Price, Volume
CLF7,01/03/1996,12:54:04,17.58
CLF7,01/03/1996,13:31:19,17.58
CLF7,01/03/1996,15:07:42,17.57
CLF7,01/03/1996,15:07:45,17.58
CLF7,01/03/1996,15:10:03,17.58
CLF7,01/03/1996,12:54:04,17.12
CLF7,01/03/1996,13:27:39,17.58
CLF7,02/03/1996,14:35:40,17.57
CLF7,02/03/1996,12:54:04,17.57
My required output:
Symbol, Data, Time, Price, Volume
CLF7,01/03/1996,13:31:19,17.58
CLF7,01/03/1996,15:07:42,17.57
CLF7,01/03/1996,15:10:03,17.58
CLF7,01/03/1996,12:54:04,17.12
CLF7,01/03/1996,13:27:39,17.58
CLF7,02/03/1996,12:54:04,17.57
I'm trying with 2 ways. First way, I create a new array with the same size of my data. It will find the value at price (i+1) is the same value at price (i). Then, I will copy the row have price (i+1) into the new array.
dim = size(data);
data_3 = zeros(dim);
i = 1; j = 1;
data_3(i,:) = data(i,:);
for i=2:dim(1)
if data(i,4) != data(i-1, 4)
j = j+1;
data_3(j,:) = data(i,:);
end
end
data_4 = data_3([1:j], :);
With this way, I did not any change in my data. The second way, I use "if" to find the value at a price (i) and compare with price(i-1). If the value is equal, I will delete the row (i-1)
for i=2:size(data);
If data(i,4) ~ data(i-1,4);
data(i-1,4)=[];
end
end
However, I meet the error: "Conversion to logical from struct is not possible".
I'm tried to find some similar questions in forum, but it is almost found and deleted all duplicate value compared the first appeared value and keep the last one. For my requirement, I just found and deleted the duplicated value when it is continuously duplicated value.
I'm really appreciated your help.
Thanks
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Risposta accettata
Andrei Bobrov
il 9 Giu 2016
f = fopen('20160609.txt');
c = textscan(f,'%s %s %s %f','delimiter',',');
fclose(f);
t =[diff(c{end})~=0;true];
C = [c{1:3}];
out = [C(t,:),num2cell(c{end}(t))];
3 Commenti
Andrei Bobrov
il 10 Giu 2016
Modificato: Andrei Bobrov
il 10 Giu 2016
f = fopen('20160610.txt');
c = textscan(f,'%s %s %s %f %f','delimiter',',','HeaderLines',1,...
'EmptyValue',nan);
fclose(f);
C = [c{1:3}];
t = ~isnan(c{4});
C = C(t,:);
co = c{4}(t);
to =[diff(co)~=0;true];
out = [C(to,:),num2cell(co(to))]
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