Find largest array size in cell of many arrays
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RuiQi
il 17 Giu 2016
Commentato: Image Analyst
il 17 Gen 2020
I have a cell each cell storing a different sized array. How do i find the largest width and height of all the arrays ?
I tried
size(test{:}(:,1,1))
test is my cell. so meaning for all test, find the size of (:,1,1). But it is wrong of coz so help me thanks.
Like
cell{1} = 10x10 uint8
cell{2} = 10x11
cell{3} = 5x99
so
min_size_of_cell_array(cell{:}) = 5,10
like that
1 Commento
Stephen23
il 17 Giu 2016
>> C{1} = NaN(10,10);
>> C{2} = zeros(10,11);
>> C{3} = ones(5,99);
>> cellfun('size',C,1) % rows
ans =
10 10 5
>> cellfun('size',C,2) % columns
ans =
10 11 99
Risposta accettata
Andrei Bobrov
il 17 Giu 2016
C = arrayfun(@(x)rand(randi([1 20],1,2)),(1:8)','un',0);% example
[s,d] = cellfun(@size,C);
out = max([s,d]);
2 Commenti
Avik Mahata
il 13 Gen 2019
How do I convert the maximum cellarray to matrix after identifying the particular cell array?
Più risposte (1)
shashmitha lakshmi
il 16 Gen 2020
How to find the maxmimum length array between two arrays
1 Commento
Image Analyst
il 17 Gen 2020
Try this:
% Create our data, a cell array of vectors of random lengths.
for k = 1 : 100
thisLength = randi(50); % Anywhere from 1 to 50.
ca{k} = rand(1, thisLength); % Create row vector of this length.
end
% Now that data has been created,
% find the lengths of all the elements.
allLengths = cellfun(@length, ca)
% Now find the longest vector between element 15 and 35 (for example)
maxLength = max(allLengths(15:35))
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