For loop iteration help
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Hi, in my code I have
for k=1:20
% code executed with output 'image'
data.(['val' num2str(k)]) = image; % save the dataset in 'data'. Can access data.val1, ... data.val20
end
I want to write another for loop to go through 'data.val1', going to 'data.val20' to execute another script I have written i.e. for k=1:20 data.val...(value of k for iteration). Help doing this will be appreciated. Thanks.
14 Commenti
>> S(1).data = 1:3;
>> S(2).data = 3:5;
>> S(3).data = 5:7;
>> S(2).data
ans =
3 4 5
>> vertcat(S.data)
ans =
1 2 3
3 4 5
5 6 7
ajk1
il 4 Ago 2016
for k = 1:20
S(k).val = ...
end
ajk1
il 4 Ago 2016
ajk1
il 4 Ago 2016
Stephen23
il 4 Ago 2016
You are getting this error because data already exists (probably as a cell array), and then you try to access it as it it were a structure.
Do this:
data = struct();
for k = 1:20
data(k).val = ...
end
" I'm not sure how to correctly access it"
That is why I gave the link in my very first comment. It tells you how to access data in a non-scalar structure. Did you read it ?
Create a non-scalar structure:
>> S = struct();
>> for k = 1:3, S(k).val = k:2+k; end
access the data:
>> S(2).val % get the second value
ans =
2 3 4
>> vertcat(S.val) % get all values, concatenate together
ans =
1 2 3
2 3 4
3 4 5
Stephen23
il 4 Ago 2016
@ajk: a non-scalar array is like any MATLAB array: it can have whatever size you want. Just use indexing like you normally would:
S(375,91,223).val = ...
S = struct();
S(375,61,223) = struct(); % preallocate final array size
ajk1
il 4 Ago 2016
ajk1
il 4 Ago 2016
ajk1
il 4 Ago 2016
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Image Analyst
il 4 Ago 2016
Why not have your other processing or loop be a loop inside this one, and not bother about saving all your sub-images in an extra variable (a structure array or cell array)? From what you've told us so far, there is no need to save subimages in an array. Just save them in a single variable and overwrite it each time.
for k = 1 : 20
% Extract a sub-image.
subImage = myImage(......
results(k) = ProcessSubImage(subImage); % Now process it in a function.
end
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