Could someone please explain...
Mostra commenti meno recenti
...the following error? I've looked in the help files and in previous questions to no avail. I am setting up an iteration as follows:
data = csvread('results_n_solve.csv');
assert (size(data, 2) == 1, ...
'Input data must have exactly one column.');
nsys = size(data, 1);
syms n1
S = n1;
y = 450;
n0 = 1;
n2 = 4.676;
k2 = .091;
d1 = 300;
for k = 1 : nsys
F = r_dat(data((k-1) + (1:1), 1:end));
S(k,:) = solve(F);
end
Where the data is a 1 column by 101 row matrix. The function file r_dat is as follows:
function F = r_dat
theta = (2.*pi().*n1.*d1)./y;
a = n0.*n1 + n0.*n2 - n1.^2 - n1.*n2 + n0.*n1.*cos(theta) - n0.*n2.*cos(theta) + (n1.^2).*cos(theta) - n1.*n2.*cos(theta) + n0.*k2.*sin(theta) + n1.*k2.*sin(theta);
b = n1.*k2 - n0.*k2 + n0.*k2.*cos(theta) + n1.*k2.*cos(theta) - n0.*n1.*sin(theta) + n0.*n2.*sin(theta) - (n1.^2).*sin(theta) + n1.*n2.*sin(theta);
c = n0.*n1 + n0.*n2 + n1.^2 + n1.*n2 + n0.*n1.*cos(theta) - n0.*n2.*cos(theta) - (n1.^2).*cos(theta) + n1.*n2.*cos(theta) + n0.*k2.*sin(theta) - n1.*k2.*sin(theta);
d = n0.*k2.*cos(theta) - n1.*k2.*cos(theta) - n0.*k2 - n1.*k2 - n0.*n1.*sin(theta) + n0.*n2.*sin(theta) + (n1.^2).*sin(theta) - n1.*n2.*sin(theta);
F = @(x) (1./((c.^2+d.^2).^2)).*(((a.*c + b.*d).^2) + ((b.*c - a.*d).^2)) - x(1);
end
Which is sloppy yet functional (hopefully). When I run this, I receive the following error:
Error using ==> r_dat Too many input arguments.
Error in ==> n_solve at 36 F = r_dat(data((k-1) + (1:1), 1:end));
Error in ==> run at 74 evalin('caller',[script ';']);
So, what does it mean by "too many input arguments"? I don't know what its telling me, so I don't know how to begin to fix it. I've tried playing around with all the variables that are involved, but nothing changes.
Risposta accettata
Più risposte (1)
bym
il 21 Feb 2012
you have defined your function with no input arguments, therefore passing any arguments to r_dat is an error.
function F = r_dat(x,y) % <-- define r_dat inputs
Categorie
Scopri di più su Code Performance in Centro assistenza e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!