finding elements in a matrix`

I have a a matrix A= [1 3 10; 1 8 10; 2 4 9] and an array x = [2 9]. i want to check if x is present in a single row of A. In this case it is true, so continue. Can anyone help? TIA.

Answer 1

[Azzi Abdelmalek]

A= [1 3 10; 1 8 10; 2 4 9] 
x=[ 2 9]
for k=1:size(A,1)
idx=all(ismember(x,A(k,:)));
if idx
  break
end
end
idx

[Ananya Malik]

Thanks @Azzi Abdelmalek for the solution. However I have one more query. If I have X=[1 2; 3 9; 3 10; 2 4] and A. If I run the code

   for i = 1: length(X(:,1))
    x= X(i,:);
    for k=1:size(A,1)
        idx=all(ismember(x,A(k,:)));
        if idx
            break; 
        else
            s=[s; x 0];
        end
    end    
  end

The output I get is s=[1 2 0;1 2 0; 1 2 0;3 9 0; 3 9 0;3 9 0;2 4 0;2 4 0]. The result i want is s= [1 2 0; 3 9 0].

Can you please help.

Answer 2

[Thorsten]

X=[1 2; 3 9; 3 10; 2 4] 
x = [2 9];

X = X(any(ismember(X, x),2), :);
s = [X zeros(size(X,1), 1)];

You also keep the last row, because it contains a 2, a number present in x.