the next code without for loop display accurately results but when use the loop show error "Assignment has more non-singleton rhs dimensions than non-singleton subscripts", why ? and What can I do to solve this problem?
    3 visualizzazioni (ultimi 30 giorni)
  
       Mostra commenti meno recenti
    
    mohammed elmenshawy
 il 16 Ago 2016
  
    
    
    
    
    Commentato: mohammed elmenshawy
 il 24 Ago 2016
            for i=1:30
    b(i,:,:)=nonzeros(A(i,:,:));
    bb(i,:,:)=unique(b(i,:,:));
    bbb(i)=sum(bb(i,:,:))/length(bb(i,:,:));
end
1 Commento
  John BG
      
 il 17 Ago 2016
				not enough data.
Please supply the chunk of code that we can reproduce, and get the same error.
Simplify anything you don't want to explain, but without code that can be readily reproduced, you force readers to a lot of guesswork without clear aim.
Awaiting answer
Risposta accettata
  Image Analyst
      
      
 il 17 Ago 2016
        Also, look up what length() and squeeze() do (you might be surprised). Next, assign some of those things to intermediate variables before sending them into unique(), length() and other functions and see what their sizes are by using THE DEBUGGER
For example:
temp1 = bb(i,:,:);
whos temp1
temp2 = length(temp1);
whos temp2
temp3 = sum(temp1);
whos temp3
bbb(i)= temp3 / temp2;
It's just basic debugging.
3 Commenti
  Image Analyst
      
      
 il 24 Ago 2016
				Get rid of the "whos" commands and put semicolons at the end of every line to suppress echoing results to the command window.
Più risposte (0)
Vedere anche
Categorie
				Scopri di più su File Operations in Help Center e File Exchange
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!

