How to use linprog when i have variable ('A')= cell

Hello, I get the following error when i try to run the linprog command : error using linprog (line 144) LINPROG requires the following inputs to be of data type double: 'A'. All the other variables i have are double (f,b,Aeq,beq,lb) except from A which is a 35x1 cell.What can i do in order to convert A to type double.

Answer 1

[Azzi Abdelmalek]

A=cell2mat(A)

[Alexandros Samp]

I can't use cell2mat because of the dimensions. I get the following error :Dimensions of matrices being concatenated are not consistent.

[Azzi Abdelmalek]

post your code to see how A is used in linprog command

[Alexandros Samp]

v=1.003*10^(-6);
 k=0.0015;
 Hman=110.6;
 QD=LinkFlows;
 f=cell(length(find(LinkFlows>0)),1);
 Re=cell(length(find(LinkFlows>0)),1);
 Hf=cell(length(find(LinkFlows>0)),1);
 HeadLoss=cell(length(find(LinkFlows>0)),1);
 NodeElevations=d.getNodeElevations;
 NodeElevations=NodeElevations(1:end-1);
 LeastPressure=Hman-NodeElevations-35;

   for ii=1:length(find(LinkFlows>0))
       Re{ii}=4.*QD(ii)./(pi.*DiameterCell{ii}.*v);

    f{ii}=0.25./[log((5.74./(Re{ii}.^(0.9)))+(k./(3.7.*DiameterCell{ii})))].^2; 

    Hf{ii}=((0.083.*f{ii}.*QD(ii).^2)./((DiameterCell{ii}./1000).^5)); 

   end
   for j=2:length(find(LinkFlows>0))
       HeadLoss{1}=[[Hf{1}]];
       HeadLoss{j}=Hf{j};
       HeadLoss{j}=[[HeadLoss{j}] [HeadLoss{j-1}]]
%%Where A=HeadLoss a cell with a differnt number of values in each cell

[Azzi Abdelmalek]

And what line gives the error?

[Alexandros Samp]

i dont get an error from this, i just can't use the A variable in the lin prog command because its a cell. What can i do to fix this?

[Azzi Abdelmalek]

How do you want to use it with linprog? explain your problem?

[Alexandros Samp]

there are 35 nodes in a network and i have to find the optim solution for diameters.I find a range of different diameter for each pipe, each diameter represents a cost.I have an f vector with (1,112) differnt values of costs for pipes , A which is the cell with Headloss for each pipe in a network that is add up ,b is a vector (1,35) with the pressure that is needed in each node , Aeq is the length constraint for each pipe is a matrix (35,112) with zeros and 1, every pipe may be consisted of differnt diameter (example a pipe of 200 m may be x1+ x2+ x3 possible diameters),beq is the length of each pipe and lb is that each x should be greater than zero.