My rectangle should have a determined color represented by a value

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I have 2 patch objects which should be placed with a determined color (represented by a value). I did not implement it because I dont know how it works. So the rectangle 1 should have the value 50 and the rectangle 2 should have the value 75. The colorbar should start from 0 to 100. Thank you in advance.
v = [0 0; 1 0; 1 1; 0 1;5 5; 10 5;10 10;5 10];%Rectangle 1 and 2
f = [1 2 3 4; 5 6 7 8];
patch('Faces',f,'Vertices',v,'FaceColor','green')
colorbar

Risposta accettata

Stephen23
Stephen23 il 5 Set 2016
Modificato: Stephen23 il 5 Set 2016
The easiest way is to use caxis, like this:
V = [0,0;1,0;1,1;0,1;5,5;10,5;10,10;5,10];
F = [1,2,3,4;5,6,7,8];
C = [50;75];
patch('Faces',F,'Vertices',V,'FaceVertexCData',C,'FaceColor','flat')
colormap(parula)
colorbar
caxis([0,100]) % set the color limits
which generate this (you can pick whatever colormap suits you best):
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  1 Commento
Neda
Neda il 8 Nov 2017
How about if we need to change the colour of circle based on their values, and circle superimposed on the image with rectangle which does have 'Curvature',[1 1].

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Più risposte (1)

Thorsten
Thorsten il 5 Set 2016
Modificato: Thorsten il 5 Set 2016
50 and 75 are not valid colorvalues in Matlab. Valid is an RGB triplet in the range [0, 1]. So I assumed that 50 and 75 is an index into a colormap. I choose 'gray', but you can any other valid colormap, like 'parula' or 'jet', for example:
Nfaces = 2;
facecolind = [50 70];
cmap = gray(100);
for i = 1:Nfaces
patch('Faces',f(i,:),'Vertices',v,'FaceColor', cmap(facecolind(i),:))
end
colormap(cmap)
h = colorbar
h.TickLabels = h.Ticks*100
  3 Commenti
Adam
Adam il 5 Set 2016
Sounds like you want the jet colourmap then. You could create your own to be more to your taste, but jet does run from blue through green up to red.

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