How to write a function to display two messages to the user (in Matbal 2011)?

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Hello everyone. I've been reading a tutorial about Matlab 6.1 but I'm working with Matlab 2011.
(I'm sorry if I make a mistake talking about string/integer but I'm new to Matlab and I use to program in C/Java/...)
I have to write a simple function doing the following:
- it takes two string (name1 and name2)
- it returns two integer representing how many characters the two string have (size1 , size2)
- the function print two lines:
  • "Hello name1" (where name1 is what I pass to the function)
  • "Hello name2" ((where name2 is what I pass to the function)
The code (it works in Matlab 6.1) provided by the tutorial is:
function [size1,size2] = helloNames (name1,name2)
% print Hello + name 1 , Hello + name 2
[rowNumber,size1] = size(name1);
[rowNumber,size2] = size(name2);
disp(cat(2,'Hello ',name1));
disp(cat(2,'Hello ',name2));
But in Matbal 2011 it doesn't works and I've tried to modify it but I can't get the same result.
Any suggestion? And what's used for "cat"?
Thank you in advance

Risposte (3)

Sean de Wolski
Sean de Wolski il 24 Feb 2012
doc cat
for more info on cats. That looks like it should work, what error are you recieving?
More per comments
A = rand(10,15);
%example1
[junk, sizeEX1] = size(A);
%example2
[~, sizeEX2] = size(A);
%example3
[sizeEX3] = size(A);
Compare the various variables.

Srinivas
Srinivas il 24 Feb 2012
helloNames('name1', 'name2')
should work

Manuel
Manuel il 24 Feb 2012
@Srinivas.. well its' strange It works now (but I'm sure it didn't worked). Just a question: function [size1,size2] = helloNames (name1,name2) % print Hello + name 1 , Hello + name 2 [rowNumber,size1] = size(name1); [rowNumber,size2] = size(name2); disp(cat(2,'Hello ',name1)); disp(cat(2,'Hello ',name2));
give the warning "rowNumber appears to not be used"(and I understand this)..If I click fix rowNumber is replaced witch "~". What does "~" means? And what's difference there is between:
[~,size1] = size(name1);
[~,size2] = size(name2);
and
[size1] = size(name1);
[size2] = size(name2);
?
  3 Commenti
Manuel
Manuel il 24 Feb 2012
Thank you for your answer. But I can't understand the explanation.
Could you make an example please?

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