Creating an Array with nested for loops.

If I have an array say A = 1:4, how would I create a new 1 x 7 array with the following elements and structure with a nested for loop? I'm very confused.

   4   4   4   4   4   4   4
   4   3   3   3   3   3   4
   4   3   2   2   2   3   4
   4   3   2   1   2   3   4
   4   3   2   2   2   3   4
   4   3   3   3   3   3   4
   4   4   4   4   4   4   4

[Stephen23]

@Nikko Jeffreys: I edited your question and replaced the example that you just deleted. Please do not delete or edit questions so that they do not make sense. We are not your personal MATLAB help service: we are volunteers here to help everyone who reads this forum. When you edit your question and remove all useful information you make our answers useless for anyone else reading this forum, the exact people we volunteer to help.

Answer 1

[Andrei Bobrov]

A = 1:4;

m = numel(A);
[ii,jj] = ndgrid(1:2*m-1);
out = A(max(abs(ii-m),abs(jj-m))+1);

or

m = numel(A);
s = zeros(2*m-1);
s(m,m) = 1;
out = A(bwdist(s,'chessboard')+1);

or with for..end loop

m = numel(A);
out = zeros(2*m-1);
for jj = 1:m
    out(jj:m*2-jj,jj:m*2-jj) = A(m + 1 -jj);
end

Answer 2

[Stephen23]

Using a for loop:

A = 1:4;
N = numel(A);
B = NaN(2*N-1);
for k = 1:N
    B([N+k-1,N-k+1],:) = A(k);
    B(:,[N+k-1,N-k+1]) = A(k);
end

Answer 3

[KSSV]

B = ones(7) ;
B(1,:) = 4 ; B(2,2:end-1) = 3 ;B(3,3:end-2)=2 ;
B(:,1) = 4 ; B(2:end-1,2) = 3 ;B(3:end-2,3)=2 ;
B(:,end) = 4 ;B(2:end-1,end-1) = 3 ;B(3:end-2,end-2)=2 ;
B(end,:) = 4 ;B(end-1,2:end-1)=3 ;B(end-2,3:end-2)=2 ;

[KSSV]

not a deal..you can put the above in loop..