Numerical integration with a variable integration limit

Is there a way to implement the following:
f2=@(z) integral (@(x) f1(x,z) ,0 ,z);
P2=@(z) integral(f2,z,Inf);
With f2 and P2 as two separate anonymous functions? It seems z in f2 must be a scalar (not a vector), so a for loop is required to make multiple evaluations at z I can deal with that, but Matlab will not evaluate P2, giving the error: Error using integral (line 85) A and B must be floating-point scalars.
It appears that
P2Alt=@(z) integral2(@(x,z) f1(x,z), 0, z, z, Inf);
accomplishes the desired end result (z must be a scalar), but I would prefer the function f2, separate.

Risposte (2)

At first, try with "int" command and form a final function of your desired variable. Ex: f2=@(x) int (f1(x,z),z);

1 Commento

Hi Ujjal. I should have mentioned in my post that I don't have the symbolic math toolbox, so invoking int is not an option for me.

Accedi per commentare.

After giving this some thought, the following appears to be one way to solve the problem:
f2=@(z) integral(@(x) f1(x,z), 0, z);
f2Vect=@(z) arrayfun(@(z)f2(z),z); %vectorize f2
zval=0:0.1:3;
P2=zeros(1,length(zval)); %Preallocate
for i=1:length(zval)
P2(i)=integral(f2Vect,zval(i),Inf); %Evaluate the integral of f2
end

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Richiesto:

il 28 Set 2016

Risposto:

il 29 Set 2016

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