Given a matrix A = [2 5 7; 4 1 8], write a for loop that will replace all the even numbers with 0.
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Sydney
il 7 Ott 2016
Risposto: Andrei Bobrov
il 7 Ott 2016
I'm looking for something using a for loop (probably nested) and possibly mod(A,2) to determine the even numbers
What I tried: It took me a while to figure out how to format mod, but once I did I started with: for b=mod(A,2) I think tried to add a logical function (such as b==0) but it kept giving me errors. The closest thing that I could write that made sense in my head was:
for b=mod(A,2);
if b==0
A(b)=0
end
end
I would then get the error: Subscript indices must either be real positive integers or logicals.
I also couldn't figure out how to size a matrix to be the same size as a different matrix.
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Mohammad Haghighat
il 7 Ott 2016
This can be a solution using for loops:
[m,n] = size(A);
for i = 1:m
for j = 1:n
if mod(A(i,j),2) == 0
A(i,j) = 0;
end
end
end
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James Tursa
il 7 Ott 2016
This is obviously a homework post. It is discouraged to do homework problems for others on this forum. Helping OP with concepts, correcting their code, etc is all within the spirit of this forum. But doing the entire problem outright for them is not.
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Andrei Bobrov
il 7 Ott 2016
A(rem(A,2)==0)=0;
or with loop
for ii = 1:numel(A)
if rem(A(ii),2) == 0
A(ii) == 0;
end
end
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