how I can finish randomly repeated values in a matrix

Hi I have a matrix

A=[1 0;
   1 3;
   2 8;
   2 3;
   1 8;
   5 6;
   6 5;
   5 9;
   6 9]

, how I can end up repeated values in column one no matter if values repeat in column two. Please help me I am new and not know to much about matlab.

[Image Analyst]

I don't know what that means. You already did end up with repeated values. Just look. The 1, 2, 5, and 6 all are repeated. So you already did it and I don't know what help you need.

[Ghulam Murtaza]

I mean how we finish those values which are repeated in column one and get new matrix in which column one has no repeated values

[Image Analyst]

What does "finish" mean? Why is the original array unfinished or partial??? What do you need to add to it to "finish" it? Please show what you'd like as an output array to eliminate any uncertainty in what you want.

Answer 1

[KSSV]

[C,ia,ib]=unique(A(:,1));

doc unique

[Ghulam Murtaza]

This does not give me answer according to my requirements, I want to know how i get remaining matrix when repeated values vanish i.e. how I get like this A=[1 0; 1 3; 2 8; 5 6; 6 9]. Now repeated values are vanished please help in this way. thanks in advance.

[KSSV]

Read about unique...it will give you what you want.

[C,ia,ib]=unique(A(:,1));

iwant = A(ia,:);