Maximum of my own function

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Piotr Grzybowski
Piotr Grzybowski il 16 Ott 2016
Modificato: Marc Jakobi il 16 Ott 2016
Using matlab find maximal values of functions f1 and f2 given by following formulas:
f1'(x) = 5x + 2
f2'(x) = 6x^2 - 3
f1(0) = f2(0) = 100
From my point of view there is of course nothing to use Matlab, both functions f1 and f2 goes to infinity of course but my teacher gave me that exercise.
I tried to solve this with "sym" "symfun" classes, I can count integrals deviratives, but how to get MAX of function on range (-inf, inf)?
Or maybe I've understood exercise bad? Hope for small help, thx for yout time!
  3 Commenti
Piotr Grzybowski
Piotr Grzybowski il 16 Ott 2016
Yes, I forgot about it.
f1' is a derivative of f1. But in fact it doesn't change anything in this case.
Not always it will be infinity, how about f(x) = -x^2 + 4 on range x in [-inf, inf] the maximum is 4.
Marc Jakobi
Marc Jakobi il 16 Ott 2016
Are you sure you are supposed to find the maximal values and not the extrema?

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Marc Jakobi
Marc Jakobi il 16 Ott 2016
Modificato: Marc Jakobi il 16 Ott 2016
syms x
f1 = 5*x + 2;
F1 = int(f1); % integrate
x_ext = solve(f1 == 0); % solve for x = 0
% limits for x --> -inf & inf
m1 = limit(F1, inf);
m2 = limit(F1, -inf);
% evaluate F1 at extreme point
m3 = subs(F1, x_ext);
% compare results
Maxf1 = max(double([m1; m2; m3]));
f2 = 6*x^2 - 3;
F2 = int(f2);
x_ext = solve(f2 == 0);
m1 = limit(F2, inf);
m2 = limit(F2, -inf);
m3 = subs(F2, x_ext);
Maxf2 = max(double([m1; m2; m3]));
I don't know how F1(100) == F2(100) = 0 would be relevant, though.

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