Capturing outputs from Loops
1 visualizzazione (ultimi 30 giorni)
Mostra commenti meno recenti
Joe Bannen
il 25 Ott 2016
Commentato: Steven Lord
il 25 Ott 2016
Hi
I have produced some code but now need to look at how it performs under various changes in input. This (I hope!) is best done by using loops. Capturing the various outputs and plotting them is where I am stuck!
for n=1:0.1:10
% Various Functions
error1=
error2=
end
error1 and error2 are produced and work well in isolation. I need to vary n and capture error1 and error2 for each n. Plotting error1 and error2 against n would be the end target.
I can't quite see how to do this!
Any help in how to do this would be very welcome. How to measure and capture the tic/toc for each n would be useful as well.
Cheers
Joe
0 Commenti
Risposta accettata
Alexandra Harkai
il 25 Ott 2016
To keep track of error1/2 and times, you can maintain an array for each of them:
error1 = zeros(91,1);
error2 = zeros(91,1);
time = zeros(91,1);
for n=1:0.1:10
tic;
% Various Functions
m = n*10-9;
t(m) = toc;
error1(m)= <first error>;
error2(m)= <second error>;
end
plot([error1, error2, t]);
Since n is not always an integer, m=n*10-9 gives an integer indexing.
1 Commento
Steven Lord
il 25 Ott 2016
Rather than multiply a decimal number to get an index (which does NOT always work) consider iterating over a vector of integer values and transforming the elements of that vector into a decimal.
for n = 1:0.1:5
n2 = 10*n-9;
disp([n, n2])
if n2 ~= round(n2)
fprintf('10*(%g)-9 returns %d%+g.\n', n, round(n2), n2-round(n2));
end
end
Compare with:
for n2 = 1:41
n = (n2+9)/10;
disp([n, n2])
if n2 ~= round(n2)
fprintf('10*(%g)-9 returns %d%+g.\n', n, round(n2), n2-round(n2));
end
end
Più risposte (0)
Vedere anche
Categorie
Scopri di più su Loops and Conditional Statements in Help Center e File Exchange
Prodotti
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!