Finding intersection point of the lines

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Hi I have data sets for two lines. i.e. x1,y1 and x2,y2. So i can plot the lines using these point data sets. I would like to know the point (x,y)where these lines intersect each other. Please note that i have tried both [x,y]=intersections(x1,y1,x2,y2); and [x,y]=curveintersect(x1,y1,x2,y2);
i would appreciate if you can tell me the exact command for this purpose.
Regards

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Jonathan Sullivan
Jonathan Sullivan il 2 Mar 2012

Più risposte (4)

Jorge Celedón
Jorge Celedón il 13 Dic 2018
Modificato: madhan ravi il 13 Dic 2018
  2 Commenti
Nicholas Ayres
Nicholas Ayres il 26 Gen 2022
Heads up to people who find this. This requires the Mapping Toolbox
Vladimir Jara
Vladimir Jara il 23 Set 2022
thanks for the heds up!

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Andrei Bobrov
Andrei Bobrov il 5 Mar 2012
data = rand(20,3);
x1 = sort(data(:,2));
x2 = sort(data(:,3));
y = data(:,1);
pp = interp1(x1,y,'linear','pp');
pp2 = interp1(x2,y,'linear','pp');
xx = xx(max(x1(1),x2(1)) <= xx & min(x1(end),x2(end)) >= xx);
func = @(x)ppval(pp,x)-ppval(pp2,x);
xb = xx([true; diff(func(xx) > 0) ~= 0]);
i1 = hankel(1:2,2:numel(xb));
xout = arrayfun(@(z)fzero(func, xb(i1(:,z))), (1:size(i1,2))' )

mohammed wasiullah
mohammed wasiullah il 5 Apr 2017
how to find the intersection between the curve and the straight ?
  1 Commento
Tan  Kah Loon
Tan Kah Loon il 18 Apr 2017
Example,y1=x^2+2x+3,y2=2x^2+3x+4 , you have to combine two eq and you get ((x^2+X+1)), type f=[1 1 1] to get the polynomials func and roots (f) for its roots.Next, you have to type your 1st equation into p=[1 2 3], after that, pvals=polyval (p,-0.5) and you will find the 1st intersection. The 2nd intersection use back the same method to find.

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Preetham Manjunatha
Preetham Manjunatha il 8 Feb 2022
Here is the link to find the intersection point of two line segments/lines. A fast two line intersection point finder based on the line parametric space. Finds the intersection point between two lines if it exists or else submits NaN.

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