How would one reverse the order of an array using a while loop?

For this homework question I am asked to write a program using the while loop that will display a given row or column vector in reverse.

Answer 1

[Asad (Mehrzad) Khoddam]

if v is the vector:

n=length(v);
while n>0
   disp(v(n));
   n=n-1;
end

[Justin Keach]

Thank you! That works, but now I need to convert each output back into a vector so that if v=[1 2 3 4] my answer will return as v1= [4 3 2 1]. My current attempts have only returned my row vector as the final element/final output of the loop.

[Justin Keach]

v=Array2;
k=length(v);
while k>0;
   disp(v(k));
   k=k-1;
end
disp(['The original array was: ' mat2str(v)]);

Answer 2

[Walter Roberson]

Supposed the length of your vector is L. Then you want to copy position j to position L-j+1 in the new vector. For example, length 6, position 1 gets written to position 6-1+1 = 6; position 2 gets written to position 6-2+1 = 5, position 3 to position 6-3+1 = 4, and so on.

[Justin Keach]

How would you implement this into a while loop? I understand what you mean, but I'm not sure how to write it in a program.

[Walter Roberson]

In your code above,

k=length(v);

and then

L = k;

and then entry k of input corresponds to entry L-k+1 of output.