Returning the same token twice in regex expression

By parsing the string 'avcadebc', how can I get regexp to return two instances of 'bc' knowing that 'a' occurs twice?

This is what I've attempted, but this is only returns a single 'bc':

'(?:a.*)(bc)'

The code I'm using-

a = 'avcadebc';
b = regexp(a, '(?:a.*)(bc)', 'tokens');

Thanks.

[Jan]

The question is not clear: What does "capture 'bc' twice" mean, if you are looking for 'a'? What is the wanted result?

[Armando]

I'd like regexp to return a cell array consisting of 'bc' and 'bc'.

[Nick Counts]

Armando, it is not clear to us what rule you are trying to create.

Is this the rule you are after?

IF a string contains both 'a' AND 'bc' 
THEN return 'bc' for each instance of 'a'

?

[Armando]

Sorry about the confusion. You have it correct.