I need help with a checker board pattern

I have a code that lets the user input the size of the squares, the dimension of the pattern, and the two colors. The problem I am having is that I can not figure out how to properly have each square alternate between the colors and how to properly have all the squares in the dimension.

This is the code for the plot of the checkerboard pattern that I have so far:

N=4;

S=0;

theta=zeros(1,N);

for k=1:N

theta(k)=2*pi*(k-1)/N;

end

for m=1:D

    x1=(R*cos(theta+pi/4)/sqrt(2))+S;

    y1=(R*sin(theta+pi/4)/sqrt(2))+S;

    plot(x1,y1);

    fill(x1,y1,C1);

    hold;

    x2=(R*cos(theta+pi/4)/sqrt(2))+S;

    y2=(R*sin(theta+pi/4)/sqrt(2));

    plot(x2,y2);

    fill(x2,y2,C2);

    hold;

    x3=(R*cos(theta+pi/4)/sqrt(2));

    y3=(R*sin(theta+pi/4)/sqrt(2))+S;

    plot(x3,y3);

    fill(x3,y3,C2);

    hold;    

    S=S+R;

end

R is the Size of the square

D is the Dimension Size

C1 and C2 are the colors

How would I go about fixing this code to make sure that I can satisfy all requirements?

[John D'Errico]

Why are you working in polar coordinates to create a checkerboard?

[Rafael Perales]

Because one of the requirements is to inscribe the square into a circle than to rotate by a phase to make a pattern out of those squares

Answer 1

[Image Analyst]

Why not use the checkerboard() function?

[Rafael Perales]

I am using colors like red and green not just black and white

[Image Analyst]

So? You can use ind2rgb() to make certain gray levels into certain colors.

[Rafael Perales]

But doesn't the checkerboard function just create and image not a plot on a graph?

[Image Analyst]

checkerboard() creates an image. In my mind, and I think most people's minds, when we think of a checkerboard we think of an image, like if you were looking at a chessboard or checkerboard. Not sure what you mean by a plot. Can you show us what a plot might look like?

[Rafael Perales]

Ok here is basically what I'm trying to do. Basically this is 2x2 version of what I'm trying to do.

The code I used for this is:

N=4;

R=2;

theta=zeros(1,N);

for k=1:N

    theta(k)=2*pi*(k-1)/N;

end

x1=(R*cos(theta+pi/4)/sqrt(2))+R;

y1=(R*sin(theta+pi/4)/sqrt(2))+R;

plot(x1,y1);

fill(x1,y1,'y');

x2=(R*cos(theta+pi/4)/sqrt(2))+R;

y2=(R*sin(theta+pi/4)/sqrt(2));

plot(x2,y2);

fill(x2,y2,'b');

x3=(R*cos(theta+pi/4)/sqrt(2));

y3=(R*sin(theta+pi/4)/sqrt(2))+R;

plot(x3,y3);

fill(x3,y3,'b');

x4=(R*cos(theta+pi/4)/sqrt(2));

y4=(R*sin(theta+pi/4)/sqrt(2));

plot(x4,y4);

fill(x4,y4,'y');